# In Fig. 9.35,

Given,

AB divides DAC in the ratio 1: 3

DAB: BAC = 1: 3

DAC + EAC = 180o

DAC + 108o = 180o

DAC = 180o – 108o

= 72o

DAB = * 72o = 18o

BAC = * 72o = 54o

In DAB + ADB + ABD = 180o

18o + 18o + ABD = 180o

36o + ABD = 180o

ABD = 180o – 36o

= 144o

ABD + ABC = 180o (Linear pair)

144o + ABC = 180o

ABC = 180o – 144o

= 36o

In BAC + ABC + ACB = 180o

54o + 36o + x = 180o

90o + x = 180o

x = 180o – 90o

= 90o

Thus, x = 90o

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Prove that the anRS Aggarwal & V Aggarwal - Mathematics

If the sides of aRD Sharma - Mathematics

D is any point onNCERT Mathematics Exemplar

In a triangle RD Sharma - Mathematics

In Δ ABCRD Sharma - Mathematics

In Δ PQRRD Sharma - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

Prove that the peRD Sharma - Mathematics

In Fig. 10.25, <iRD Sharma - Mathematics

In a <span lang="RD Sharma - Mathematics