Q. 53.9( 14 Votes )

In Fig. 9.35, AB divides DAC in the ratio 1: 3 and AB =DB. Determine the value of x.


Answer :

Given,

AB divides DAC in the ratio 1: 3


DAB: BAC = 1: 3


DAC + EAC = 180o


DAC + 108o = 180o


DAC = 180o – 108o


= 72o


DAB = * 72o = 18o


BAC = * 72o = 54o


In


DAB + ADB + ABD = 180o


18o + 18o + ABD = 180o


36o + ABD = 180o


ABD = 180o – 36o


= 144o


ABD + ABC = 180o (Linear pair)


144o + ABC = 180o


ABC = 180o – 144o


= 36o


In


BAC + ABC + ACB = 180o


54o + 36o + x = 180o


90o + x = 180o


x = 180o – 90o


= 90o


Thus, x = 90o


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz | Lines and Angles43 mins
Quiz | Lines and Angles40 mins
Quiz | Angle Sum Property of Triangle40 mins
NCERT | Angle Sum Property44 mins
Matter and Its Classification34 mins
Lines and Angles45 mins
NCERT | Intersecting and Non Intersecting lines)41 mins
NCERT | Discussion on Lines And Angles45 mins
Know About Transversal and Parallel lines42 mins
Champ Quiz | Triangle Inequality27 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses