Answer :

Step1: Draw circle of radius 6cm with center A, mark point C at 10 cm from center

Step 2: find perpendicular bisector of AC

Step3: Take this point as center and draw a circle through A and C

Step4:Mark the point where this circle intersects our circle and draw tangents through C

Length of tangents = 8cm

AE is perpendicular to CE (tangent and radius relation)

In ΔACE

AC becomes hypotenuse

AC^{2} = CE^{2} + AE^{2}

10^{2} = CE^{2} + 6^{2}

CE^{2} = 100-36

CE^{2} = 64

CE = 8cm

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