# Show that the sequence defined by is an A.P., find its common difference.

Put n = 1

A1= 5(1) – 7

= -2

Put n = 2

A2= 5(2) – 7

= 10 – 7 = 3

Put n = 3

A3= 5(3) – 7

= 15 – 7 = 8

Common difference, d1= a2 – a1= 3 – (-2) = 5

Common difference, d2= a3 – a2= 8 – 3 = 5

Since, d1 = d2 and Common difference = 5

Therefore, it’s an A.P.

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