Answer :

Put n = 1

A1= 5(1) – 7


= -2


Put n = 2


A2= 5(2) – 7


= 10 – 7 = 3


Put n = 3


A3= 5(3) – 7


= 15 – 7 = 8


Common difference, d1= a2 – a1= 3 – (-2) = 5


Common difference, d2= a3 – a2= 8 – 3 = 5


Since, d1 = d2 and Common difference = 5


Therefore, it’s an A.P.


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