Q. 44.4( 113 Votes )

How many te

Answer :

First term a = -6


Second term = -11/2


Let d be the common difference.


d = Second term – First term


d = -11/2 – (-6) = 6 – 11/2 = 1/2


Sn = Sum of n terms of AP = -25









n2 – 25n + 100 = 0


n2 – 20n – 5n + 100 = 0


n × (n – 20) – 5 × (n – 20) = 0


(n – 20) × (n – 5) = 0


n = 20 or 5

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

There are n A.M.sRD Sharma - Mathematics

If x, y, z are inRD Sharma - Mathematics

Insert 7 A.M.s beRD Sharma - Mathematics

The 10th</suRD Sharma - Mathematics

Insert five numbeRD Sharma - Mathematics

The 4th</supRD Sharma - Mathematics

Insert 4 A.M.s beRD Sharma - Mathematics

Show that x2RD Sharma - Mathematics

An A.P. consists RD Sharma - Mathematics

How many terms arRS Aggarwal - Mathematics