Answer :


On cross multiplication

2(a - 8) = 3(a - 3)

2a - 16 = 3a - 3

On transposing constant terms to RHS and variables to LHS, we get

2a - 3a = 16 - 9

-a = 7

a = -7

Check:


Taking LHS



On substituting a = -7, we get



Taking RHS



On substituting a = -7, we get



We got LHS = RHS

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