Answer :
Construct Line OC = radius
OP = OQ = OC = radius
OC∥AP and AC∥OP and
Thus AP = OP = radius
As AP = OP and ∠P = 90°
ΔOAP is isosceles triangle
∴ ∠ PAO = ∠POA = 45°
Also ∠ PAC = 90°
∠OAC = 45° ---1
Also AB is perpendicular to OC
∠OCA = 90°
In ΔAOC
∠OCA + ∠OAC + ∠COA = 180°
45 + 90 + ∠COA = 180°
∠COA = 45°
Similarly
∠BOC = 45°
∴ ∠AOB = 90°
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
History - Concept and Questions57 mins
Corrosion: Types, Pros and Cons41 mins
Introduction to Linear Equations in Two Variables62 mins
Revision on Substitution and Elimination Method44 mins
Trigo Marathon Part 146 mins
Arithmetic Progression and 'nth' Term of AP55 mins
Nelson Mandela : Long Walk to Freedom42 mins
Economics - Concept and Questions59 mins
















Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
Choose the correc
AP- MathematicsChoose the correc
AP- MathematicsProve that the ta
AP- MathematicsChoose the correc
AP- MathematicsChoose the correc
AP- MathematicsChoose the correc
AP- MathematicsIn a right triang
AP- MathematicsDraw a circle wit
AP- MathematicsDraw a tangent to
AP- Mathematics