Let O be center, OP be radius.Applying PythagorasPQ = 24, OQ = 25OQ2 = OP2 + PQ2252 = OP2 + 242625 = OP2 + 576OP2 = 49OP = 7 cmRadius of Circle = 7 cm

Q. 1 B4.6( 9 Votes )

Choose the correc

Class 10th AP- Mathematics 9. Tangents and Secants to a Circle

Answer :

Let O be center, OP be radius.

Applying Pythagoras

PQ = 24, OQ = 25

OQ² = OP² + PQ²

25² = OP² + 24²

625 = OP² + 576

OP² = 49

OP = 7 cm

Radius of Circle = 7 cm

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