1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18

Q. 144.6( 57 Votes )

Insert five numbers between 8 and 26 such that the resulting sequence is an A.P.

Class 11th NCERT - Maths 9. Sequences and Series

Answer :

Let A₁, A₂, A₃, A₄, and A₅ be five numbers between 8 and 26

such that 8, A₁, A₂, A₃, A₄, A₅, 26 is an A.P.

Here, First term = a = 8,

Last Term = b = 26,

Total no. of terms = n = 7

Therefore, 26 = 8 + (7 – 1) d

⇒ 6d = 26 – 8 = 18

⇒ d = 3

A₁ = a + d = 8 + 3 = 11

A₂ = a + 2d = 8 + 2 × 3 = 8 + 6 = 14

A₃ = a + 3d = 8 + 3 × 3 = 8 + 9 = 17

A₄ = a + 4d = 8 + 4 × 3 = 8 + 12 = 20

A₅ = a + 5d = 8 + 5 × 3 = 8 + 15 = 23

Thus, the required five numbers between 8 and 26 are 11, 14, 17, 20, and 23.

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

PREVIOUSIf the sum of n terms of an A.P. is 3n2 + 5n and its mth term is 164, find the value of m.NEXTIf is the A.M. between a and b, then find the value of n.

RELATED QUESTIONS :

A man deposited Rs 10000 in a bank at the rate of 5% simple interest annually. Find the amount in 15^th year since he deposited the amount and also calculate the total amount after 20 years.

NCERT - Maths

In a certain A.P. the 24^th term is twice the 10^th term. Prove that the 72^nd term is twice the 34^th term.

RD Sharma - Mathematics

Find the second term and nth term of an A.P. whose 6^th term is 12 and 8^th term is 22.

RD Sharma - Mathematics

There are n A.M.s between 3 and 17. The ratio of the last mean to the first mean is 3 : 1. Find the value of n.

RD Sharma - Mathematics

The sum of first n terms of two A.P.’s is in the ratio (7n + 2) : (n + 4). Find the ratio of their 5th terms.

RD Sharma - Mathematics

If x, y, z are in A.P. and A₁is the A.M. of x and y, and A₂ is the A.M. of y and z, then prove that the A.M. of A₁ and A₂ is y.

RD Sharma - Mathematics