Q. 144.5( 67 Votes )

Insert five

Answer :

Let A1, A2, A3, A4, and A5 be five numbers between 8 and 26


such that 8, A1, A2, A3, A4, A5, 26 is an A.P.


Here, First term = a = 8,


Last Term = b = 26,


Total no. of terms = n = 7


Therefore, 26 = 8 + (7 – 1) d


6d = 26 – 8 = 18


d = 3


A1 = a + d = 8 + 3 = 11


A2 = a + 2d = 8 + 2 × 3 = 8 + 6 = 14


A3 = a + 3d = 8 + 3 × 3 = 8 + 9 = 17


A4 = a + 4d = 8 + 4 × 3 = 8 + 12 = 20


A5 = a + 5d = 8 + 5 × 3 = 8 + 15 = 23


Thus, the required five numbers between 8 and 26 are 11, 14, 17, 20, and 23.


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