Q. 104.7( 43 Votes )

The donations giv

Answer :

We have


For mean:


Mean is given by




Mean = 11.25


For median:


Total observation, N = 80


Since, N is even (that is, 80 is even),




&



Cumulative frequencies = 50 is just greater than 40 and 41.


And cumulative frequencies, 50 falls in donation by each student, 10.


Median = 10


For mode:


Mode is the value having highest frequency in the data.


From the table given above, 20 is the greatest frequency in the given frequencies.


Thus, the corresponding value in ‘donation by each student’, 10 is the mode.


Mode = 10


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz | Median and ModeQuiz | Median and ModeQuiz | Median and Mode29 mins
Bonus Questions on Measures of Central TendencyBonus Questions on Measures of Central TendencyBonus Questions on Measures of Central Tendency43 mins
Quiz | Basics of  MeanQuiz | Basics of  MeanQuiz | Basics of Mean37 mins
NCERT | Imp Qs Discussion on StatisticsNCERT | Imp Qs Discussion on StatisticsNCERT | Imp Qs Discussion on Statistics43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

There are four unAP- Mathematics

Number of villageAP- Mathematics

The heights of boAP- Mathematics

The mean (averageAP- Mathematics

If the mean of thAP- Mathematics

Weights of parcelAP- Mathematics

On the occasion oAP- Mathematics

AFLATOUN social aAP- Mathematics

Number of familieAP- Mathematics

Centuries scored AP- Mathematics