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# The angle of elevation of the top of a building from the foot of the tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 60°. If the tower is 50 m high, find the height of the building

Answer :

Let us take AB as building and

Let us take DC as tower = 50 m,

∠ACB = 30°

And,

∠ DBC = 60°;

AB= ?

In Δ DCB;

where, p = perpendicular and b = base

In Δ ACB

where p = perpendicular and b = base

AB= 16.67 m

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