Q. 83.8( 9 Votes )

The electricity bills (in rupees) of 25 houses in a locality are given below. Construct a grouped frequency distribution table with a class size of 75.

170, 212, 252, 225, 310, 712, 412, 425, 322, 325, 192, 198, 230, 320, 412, 530, 602, 724, 370, 402, 317, 403, 405, 372, 413

Answer :

Given are electricity bills (in rupees) of 25 houses in locality.

To construct a grouped frequency distribution table with a class size of 75, note down smallest and largest number from the data.


Smallest number = 170


Largest number = 724


So, let the class interval start from 150.


Then, add 75 to 150 = 150 + 75 = 225


First class interval = 150-225


Similarly,


Second class interval = 225-300 [ 225 + 75 = 300]


And so on…


For frequencies, count the occurrence of the numbers lying between the particular class interval.


Let us construct a table in order to show these class intervals along with their frequencies.



Thus, this is the required frequency distribution table.


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