Q. 74.3( 274 Votes )

From a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a 20 m high building are 45° and 60° respectively. Find the height of the tower.

Answer :


Since the building is vertical.
∠QPO = 90°

In a right-angled triangle, we know,

In ∆OPQ,


tan 45° =


1 =


OP = 20 -------(1)


Now in ∆OPR


tan 60° =


=


=


20√3 = h+20


h = 20√3-20


h = 20(√3-1) m.


Therefore the height of transmission tower is 20(√3-1) m.

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