# In figure, AT is a tangent to the circle with center 0 such that OT = 4 cm and ∠OTA = 30°. Then, AT is equal toA. 4 cmB. 2 cmC. D.

Given : A circle with center O and a tangent AT passing through point A on the circle, also OT = 4 cm and OTA = 30°

To find : Length of AT

Construction : Join OA.

We know that, the tangent at any point of a circle is perpendicular to the radius through the point of contact.

So we have

OA AT

Therefore, OAT = 90°

In OAT

Using

We have,

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