Answer :


Let AB be the boy, and CD be the building and angles becomes 60°, as the boy reaches E.


The angle of elevation in first case = 30°


And


The angle of elevation, in the second case = 60°.


Difference between bases in the first case and second case will give the distance covered by the boy.


1st case:
here p = height of the building - the height of the boy  
          = 30 - 1.5
          = 28.5 m





b = 28.5√3 


2nd case:





Hence, the distance covered by the boy:


= 28.5




= 19√3 m

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