Q. 5 B4.8( 52 Votes )

# Find the area of each of the following fields. All dimensions are in metres.

Answer :

As we know that,

And we have 3 triangles here, namely, Δ EFH, Δ AJG, Δ AKB

Therefore,

⇒ Ar(Δ EFH) = 400 sq. m

Similarly,

⇒ Ar(Δ AKB) = 750 sq.m

And,

⇒ Ar(Δ AJG) = 1400 sq. m

Also, there are three trapeziums, namely, EICD, ICBK and FHJG

⇒ Ar(EICD) = 3600 sq.m

Also,

⇒ Ar(ICBK) = 2100 sq.m

And,

⇒ Ar(FHJG) = 2400 sq.m

Now, the area of the given figure is equal to the sum of the individual areas of triangles and trapeziums.

⇒ Req. area = Ar(Δ EFH) + Ar(Δ AKB) + Ar(Δ AJG) + Ar(EICD) + Ar(ICBK) + Ar(FHJG)

⇒ Req. area = 400 + 750 + 1400 + 3600 + 2100 + 2400

⇒ Req. area = 10650 sq.m

∴ the area of the given figure is 10650 sq.m

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