# A building subtends a right angle at the top of a pole on the other side of the road. The line joining the top of the pole and the top of the building makes an angle of 60° with the vertical. If the width of the road is 45 m, find the height of the building.

Given: Width of the road = 45m

In right Δ BCD, we have

CD = 15√3 m

CD = BE = 15√3 m

Now, In ΔAED, we have

AE = 45√3 m

Now, the height of the building = AE + BE = 45√3 + 15√3

= √3(45 + 15)

= 60√3 m

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