Q. 54.7( 17 Votes )

Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°. Determine all the angles of the triangle.

Answer :

Given that,

Two angles are equal and third angle is greater than each of those angles by 30o.


Let, x, x, x + 30o be the angles of the triangle.


We know that,


Sum of all angles of triangle is 180o


x + x + x + 30o = 180o


3x + 30o = 180o


3x = 180o – 30o


3x = 150o


x = 50o


Therefore,


The angles are:


x = 50o


x = 50o


x + 30o = 50o + 30o


= 80o


Therefore, the required angles are 50o, 50o, 80o.


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