# Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°. Determine all the angles of the triangle.

Given that,

Two angles are equal and third angle is greater than each of those angles by 30o.

Let, x, x, x + 30o be the angles of the triangle.

We know that,

Sum of all angles of triangle is 180o

x + x + x + 30o = 180o

3x + 30o = 180o

3x = 180o – 30o

3x = 150o

x = 50o

Therefore,

The angles are:

x = 50o

x = 50o

x + 30o = 50o + 30o

= 80o

Therefore, the required angles are 50o, 50o, 80o.

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