Answer :


Let AB be the Flagstaff and CD be the vertical tower


let the height of the tower, CD = h


AB = EC = 12 m


and the distance between Flagstaff and tower = 12 m


Hence, BC = AE = 12 m


Now, In Δ ABC, we have




tan x = tan 45°


x = 45° …(i)


Now, In ΔADE, we have



[from(i)]




DE = 12 m


Hence, the height of the tower, CD = DE + CE = 12 + 12 = 24m


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