For what value of

Given:

For f(x) is continuous at x = 2 & f(2) = k

If f(x) to be continuous at x = 2,we have to show, f(2)^–=f(2) ⁺ =f(2)

LHL = f(2)^– ₌

⇒ (5–4×0)

⇒ 5 ...(1)

RHL = f(2) ⁺ =

⇒ (5 – 3 × 0)

⇒ 5 ...(2)

Since , f(x) is continuous at x = 2 & f(2) = k

k = 5