For what value of

Given:

For f(x) is continuous at x = 2 & f(2) = k

If f(x) to be continuous at x = 2,we have to show, f(2)=f(2) + =f(2)

LHL = f(2) =

(5–4×0)

5 ...(1)

RHL = f(2) + =

(5 – 3 × 0)

5 ...(2)

Since , f(x) is continuous at x = 2 & f(2) = k

k = 5

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