Q. 41 C4.7( 3 Votes )
Two men are on the opposite sides of a tower. They measure the angles of elevation of the tower as 25° and 40° respectively. If the height of the tower is 35 m, find the distance between two men; having given tan 25° = 0.4663 and tan 40° = 0.8391.
In right Δ ABP, we have
⇒ x = 75.058 m
⇒ x = 75.06
In the right Δ ABQ, we have
⇒ y = 41.71 m
So, the distance between two men = x + y
= 75.06 + 41.71
= 116.77 m (approx.)
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