# The angles of a triangle are arranged ascending order of magnitude. If the difference between two consecutive angles is 10°, find the three angles.

Given that,

The difference between two consecutive angles is 10o.

Let, x, x + 10 and x + 20 be the consecutive angles differ by 10o.

We know that,

x + x + 10 + x + 20 = 180o

3x + 30o = 180o

3x = 180o – 30o

3x = 150o

x = 50o

Therefore, the required angles are:

x = 50o

x + 10 = 50o + 10o

= 60o

x + 20 = 50o + 20o

= 70o

The difference between two consecutive angles is 10o then three angles are 50o, 60o and 70o.

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