Answer :

Given:



To find: Values of sin4x


We know,


sin2 x + cos2 x = 1


cos2 x = 1 – sin2 x








Since,



cosx will be negative in first quadrant


So,



We know,


sin 2x = 2 sin x cos x


cos 2x = 2 cos2 x – 1


Therefore,


sin 4x = 2 sin 2x cos 2x


sin 4x = 2 (2 sin x cos x) (2 cos2 x – 1)










Hence, value of


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