# A tree breaks due

Let BAC be the tree.

Now, due to storm AC is broken and leans to make a shape as right-angled triangle shown in figure.

AC is the broken part of the tree and AB is the part which is still upright.

Hence,

Distance from tree foot to where top touches, BC = 8 m

And,

∠ BCA = 30o

Clearly, Sum of AB and AC will give the height of the tree.

In Δ ABC:

AC =

Hence,

AB =

Now,

Height of tree= AB + AC

=

=

rationalizing, we get

= 8√3 m

Hence, height of the tree is 8√3 m

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