Find the points on x-axis which are situated at equal distances from the points (–2, –5) and (2, –3).

We have A (–2, –5)

B (x, 0) equidistant from A and C

(y = 0 since B lies on X-axis)

C (2, –3)

Using the distance formula,

Since B is equidistant from A and C

AB = BC

Squaring both sides

8x + 16 = 0

x = –2

The required point is B (–2, 0).

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