Q. 114.3( 86 Votes )

# Write the f

Answer :

Given here are a1 = 3,

an = 3a(n – 1) + 2…………1

To find out first five terms of the sequence we will put value of n = 2, 3, 4, 5 in 1

a2= 3(3)2-1 + 2 = 3 × 3 + 2 = 11

a3 = 3a2 + 2 = 3 × 11 + 2 = 35 ( an-1 = a3-1 = a2 )

a4 = 3a3 + 2 = 105 + 2 = 107

a5 = 3a4 + 2 = 3 × 107 + 2 = 323

Hence the first five terms of the sequence are 3, 11, 35, 107, 323

And the corresponding sequence is 3 + 11 + 35 + 107 + 323 + …….

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