Q. 104.1( 346 Votes )
Two poles of equa
Let AB and DE be the two poles, and C be the point of observation.
width of road, BD = 80 m
Angle of elevation to AB, ∠ACB = 30°
Angle of elevation to DE, ∠ ECD = 60°
To find: Height of buildings AB and DE.
In Δ ACB
In Δ EDC:
We know that AB = ED as the poles are of same height.
Hence, from (i) and (ii),
cross multiplying, we get
Now, using the value of BC in (i),
AB = 20√3 m
Now from triangle EDC,
Height of Pole = 20√3 m
Distances of poles from observing point = 60 m and 20 m
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