Answer :


Let AB and DE be the two poles, and C be the point of observation.
Given, 
width of road, BD =  80 m
Angle of elevation to AB, ∠ACB = 30°
Angle of elevation to DE, ∠ ECD = 60°
To find: Height of buildings AB and DE.

In Δ ACB


In Δ EDC:


We know that AB = ED as the poles are of same height.

Hence, from (i) and (ii),


cross multiplying, we get


Now, using the value of BC in (i),

AB = 20√3 m
Now from triangle EDC,

Therefore, 
Height of Pole = 20√3 m
Distances of poles from observing point = 60 m and 20 m

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