Answer :

Given, perimeter of ∆ABC = perimeter of ∆PQR


AB + BC + CA = PQ + QR + RP


AB + 5 + 13 = 6 + 10 + 14


AB + 18 = 30


AB = 30 – 18 = 12 cm


We know that, Area of triangle = × b × h


Area of ∆ABC = × BC × AB = × 5 × 12 = 30 cm2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
RELATED QUESTIONS :

Area of a trianglNCERT - Exemplar Mathematics

<span lang="EN-USNCERT Mathematics

<img style=NCERT Mathematics

<span lang="EN-USNCERT Mathematics

In the given triaNCERT - Exemplar Mathematics

Find the area of NCERT - Exemplar Mathematics

In Fig. 9.32, areNCERT - Exemplar Mathematics

Ratio of the areaNCERT - Exemplar Mathematics

Area of an isosceNCERT - Exemplar Mathematics

In Fig. 9.41, areNCERT - Exemplar Mathematics