Answer :

The figure is given below:

In ΔABC

∠C = 45

AC = 250 m

BC = 300m

Using cosine rule

a^{2} = b^{2} + c^{2} – 2bc cos A

so, AB^{2} = AC^{2} + BC^{2} – 2 AC x BC cos C

= 250^{2} + 300^{2} – 2 x 250 x 300 x cos 45

AB^{2} = 46433.98

AB = 215.5 m

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