Answer :

Where a = first term,

r = common ratio

n = number of terms

ATQ,

r^{20} – 1 = 244(r^{10} – 1)

r^{20} – 244r^{10} + 243 = 0

r^{20} – 243r^{10} – r^{10} + 243 = 0

r^{10}(r^{10} – 1) – 243(r^{10} – 1 )= 0

⇒ r = √3 (r = 1 is not valid)

So, the common ratio is √3

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