Answer :

Given, P is the mid point of AB, so AP = 40 cm


And S is the mid point of AD, so AS = 30 cm


Area of ABCD = 80 × 60 = 4,800 cm2


Area of ∆SAP = × AP × AS = × 40 × 30 = 600 cm2


Area of 4 unshaded congruent triangles =4 × 600 cm2 = 2,400 cm2


Area of unshaded circle = ∏r2 = 3.14 × 10 × 10 = 314 cm2


Area of shaded area = 4,800 – (2,400 + 314) = 2086 cm2


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