Answer :

A. (i) Length of family room = 5.48 m

Breadth of family room = 4.57 m

Perimeter of family room = 2 (l + b) = 2 (5.48 + 4.57) = 2 × 10.05 = 20.1 m^{2}

Moulding required for family room = 20.1 m^{2}

(ii) Length of living room = 7.53 m

Breadth of living room = 3.81 m

Perimeter of living room = 2 (l + b) = 2 (7.53 + 3.81) = 2 × 11.84 = 22.68 m^{2}

Moulding required for living room = 22.68 m^{2}

(iii) Length of dining room = 5.48 m

Breadth of dining room = 5.41 m

Perimeter of dining room = 2 (l + b) = 2 (5.48 + 5.41) = 2 × 10.89 = 21.78 m^{2}

Moulding required for dining room = 20.1 m^{2}

(iv) Side of bedroom 1 = 3.04 m

Perimeter of bedroom 1 = 4 × side = 4 × 3.04 = 12.16 m^{2}

Moulding required for bedroom 1 = 12.16 m^{2}

(v) Length of bedroom 2 = 3.04 m

Breadth of bedroom 1 = 2.43 m

Perimeter of dining room = 2 (l + b) = 2 (3.04 + 2.43) = 2 × 5.47 = 10.94 m^{2}

Moulding required for dining room = 20.1 m^{2}

B. Area of family room = 5.48 × 4.57 = 25.0436 m^{2}

Cost of carpeting family room at the rate of Rs 200/m^{2} = 200 × 25.0436 =Rs. 5008.72

Area of living room = 7.53 × 3.81= 28.6893 m^{2}

Cost of carpeting living room at the rate of Rs 200/m^{2} = 200 × 28.6893 =Rs. 5737.86

Area of dining room = 5.48 × 5.41= 29.6468 m^{2}

Cost of carpeting dining room at the rate of Rs 200/m^{2} = 200 × 29.6468 =Rs. 5929.36

Area of bedroom1 = 3.04 × 3.04 = 9.2416 m^{2}

Cost of carpeting bedroom1 at the rate of Rs 200/m^{2} = 200 × 9.2416 =Rs. 1848.32

Area of bedroom2 = 3.04 × 2.43 = 7.3872 m^{2}

Cost of carpeting bedroom 2 at the rate of Rs 200/m^{2} = 200 × 7.3872 =Rs. 1477.44

C. Total perimeter of all five rooms = 20.1 + 22.68 + 21.78 + 12.16 + 10.94 = 87.66 m

Cost of moulding 1 m = Rs 500

Total cost of moulding all five rooms = 500 × 87.66 = Rs. 43,830

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