Q. 35.0( 1 Vote )

<span lang="EN-US

Answer :

Given: We have 10 numbers i.e. 0,1,2,3,4,5,6,7,8,9


To Find: Number of 3-digit numbers formed with no repetition of digits.


Conditions: No digit is repeated


Let us represent the 3-digit number



First place can be filled with 9 numbers, i.e. 1,2,3,4,5,6,7,8,9 (0 cannot be placed as it will make it a 2-digit number) = 9 ways


Second place can be filled with remaining 9 numbers (as one number is used already) = 9 ways


Similarly, third place can be filled with 8 numbers = 8 ways


Total number of 3-digit numbers which can be formed


= 9 × 9 × 8= 648


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

In how many ways RS Aggarwal - Mathematics

In how many ways RS Aggarwal - Mathematics

For a set of fiveRS Aggarwal - Mathematics

A mint prepares mRS Aggarwal - Mathematics

A sample of 3 bulRS Aggarwal - Mathematics

From among the 36RS Aggarwal - Mathematics

If 20 lines are dMathematics - Exemplar