Q. 143.7( 3 Votes )

In how many ways

Answer :

Given: We have 5 boys and 3 girls


To Find: Number of ways of seating so that 5 boys and 3 girls are seated in a row and each girl is between 2 boys


The formula used: The number of permutations of n different objects taken r at a time (object does not repeat) is


The only arrangement possible is


B__B__B__B__B


Number of ways for boys





=120


There are 3 girls, and they have 4 vacant positions


Number of ways for girls




=24


Total number of ways = 24 × 120 = 2880


In 2880 ways 5 boys and 3 girls can be seated in a row so that each girl is between 2 boys.


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