Q. 253.8( 4 Votes )

In an examination

Answer :

Candidates in mathematics are not sitting together = total ways – the


Students are appearing for mathematic sit together.


The total number of arrangements of 8 students is 8! = 40320


When students giving mathematics exam sit together, then consider


them as a group.


Therefore, 6 groups can be arranged in P(6,6) ways.


The group of 3 can also be arranged in 3! Ways.


Formula:


Number of permutations of n distinct objects among r different places, where repetition is not allowed, is


P(n,r) = n!/(n-r)!


Therefore, total arrangments are


P(6,6) × 3! = ×3!


= ×3! = ×6 = 4320.


The total number of possibilities when all the students giving


mathematics exam sits together is 4320 ways.


Therefore, number of ways in which candidates appearing


mathematics exam is 40320 – 4320 = 36000.


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