Answer :

To find: number of words starting with C and end with Y

There are 8 letters in word COURTESY.

Here the position of the letters C and Y are fixed which is 1^{st} and 8^{th}.

Rest 6 letters are to be arranged in 6 places which can be done in P(6,6).

Formula:

Number of permutations of n distinct objects among r different places, where repetition is not allowed, is

P(n,r) = n!/(n-r)!

Therefore, a permutation of 6 different objects in 6 places is

P(6,6) = = = = 720.

Therefore, total number of words starting with C and ending with Y is 720.

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