# In a textbook on mathematics there are three exercises A, B and C consisting of 12, 18 and 10 questions respectively. In how many ways can three questions be selected choosing one from each exercise?

Given: three exercises A, B and C consisting of 12, 18 and 10 questions respectively.

To find: number of ways in which three questions be selected choosing one from each exercise.

Ways of selecting one question from exercise A:12C1 (way of selecting one element from n number of elements.)

Ways of selecting one question from exercise B:18C1

Ways of selecting one question from exercise C:10C1

So number of ways of choosing one question from each exercise A ,B,C =12C1 × 18C1 × 10C1

=12 × 18 × 10

=2160

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Circular permutationsFREE Class  Lecture on Combinations49 mins  Understand Permutations like never before60 mins  Check Your progress Part 2| Interactive Quiz: Permutation & CombinationFREE Class  Fundamental Principle of Counting49 mins  Permutation & Combination (Lecture 4)FREE Class  Interactive Quiz on Combinations-02FREE Class  Interactive Quiz on Combinations50 mins  Interactive Quiz on Circular permutationsFREE Class  Permutation & Combination (Lecture 6)FREE Class
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 