# An express train takes 1 hour less than a passenger train to travel 132 km between Mysore and Bangalore (without taking into consideration the time they stop at intermediate stations). If the average speed of the express trains is 11 km / hr more than that of the passenger train, find the average speeds of the two trains.

Time = distance/speed

Now, express train takes 1 hour less than a passenger train to travel 132 km between Mysore and Bangalore. The average speed of the express trains is 11 km / hr more than that of the passenger train.

Let the average speed of passenger train be ‘a’.

132 ×(a + 11 –a) = a2 + 11a

a2 + 11a – 1452 = 0

a2 + 44a – 33a – 1452 = 0

a(a + 44) – 33(a + 44) = 0

(a + 44)(a – 33) = 0

a = 33 km/hr

Speed of express train = 44 km/hr

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Bonus Questions on Solutions of Quadratic Equations31 mins
Smart Revision | Quadratic Equations53 mins
Quiz | Knowing the Nature of Roots44 mins
Foundation | Practice Important Questions for Foundation54 mins
Take a Dip Into Quadratic graphs32 mins
Learn to Find Nature of Roots25 mins
Smart Revision | Learn to Find the Nature of Roots34 mins
Nature of Roots of Quadratic Equations51 mins
Getting Familiar with Nature of Roots of Quadratic Equations51 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses