Answer :

Let one of the natural numbers be ‘a’


Given, the numbers differ by 3.


2nd number = a + 3


a2 + (a + 3)2 = 117


a2 + a2 + 6a + 9 = 117


a2 + 3a – 54 = 0


a2 + 9a – 6a – 54 = 0


a(a + 9) – 6(a + 9) = 0


(a – 6)(a + 9) = 0


a = 6, - 9


Thus, the numbers are 6, 9


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