Q. 135.0( 4 Votes )

The product of tw

Answer :

Let the successive integral multiples of 5 be a, a + 5.


a(a + 5) = 300


a2 + 5a – 300 = 0


a2 + 20a – 15a – 300 = 0


a(a + 20) – 15(a + 20) = 0


(a + 20)(a - 15) = 0


a = - 20, 15


Numbers are, -20, -15 or 15, 20


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