Q. 44.6( 18 Votes )

For what value of

Answer :


For the above expression to be a perfect square, D = b2 – 4ac = 0


(2k + 4)2 – 4 × (4 – k)(8k + 1) = 0


4k2 + 16k + 16 + 32k2 – 124k – 16 = 0


36k2 – 108k = 0


36k(k – 3) = 0


k = 0, 3


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