# Find the sum to first n terms of an A.P. whose kth term is 5k + 1.

As it is given that kth term of the AP = 5k + 1

ak = a + (k – 1)d

5k + 1 = a + (k – 1)d

5k + 1 = a + kd – d

Now, on comparing the coefficient of k, we get

d = 5

and a – d = 1

a – 5 = 1

a = 6

We know that,

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