Q. 74.3( 6 Votes )

# The shadow of a tower standing on a level plane is found to be 50m longer when sun’s elevation is 300 than when it is 600. Find the height the tower.

Let SQ = h be the tower.

SPQ = 30° and SRQ = 60°

According to the question, the length of shadow is 50 m long hen angle of elevation of the sun is 30° than when it was 60°. So,

PR = 50 m and RQ = x m

So in ∆SRQ, we have

In ∆SPQ,

Substituting the value of x in the above equation, we get

503+h = 3h

503 = 3h - h

3h - h = 50√3

2h = 503

h = (503)/2

h = 253

Hence, the required height is 25√3 m.

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