Answer :

Let SQ = h be the tower.

SPQ = 30° and SRQ = 60°

According to the question, the length of shadow is 50 m long hen angle of elevation of the sun is 30° than when it was 60°. So,

PR = 50 m and RQ = x m

So in ∆SRQ, we have

In ∆SPQ,

Substituting the value of x in the above equation, we get

503+h = 3h

503 = 3h - h

3h - h = 50√3

2h = 503

h = (503)/2

h = 253

Hence, the required height is 25√3 m.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses