Q. 74.3( 6 Votes )

The shadow of a tower standing on a level plane is found to be 50m longer when sun’s elevation is 300 than when it is 600. Find the height the tower.

Answer :

Let SQ = h be the tower.

SPQ = 30° and SRQ = 60°


According to the question, the length of shadow is 50 m long hen angle of elevation of the sun is 30° than when it was 60°. So,


PR = 50 m and RQ = x m



So in ∆SRQ, we have







In ∆SPQ,






Substituting the value of x in the above equation, we get




503+h = 3h


503 = 3h - h


3h - h = 50√3


2h = 503


h = (503)/2


h = 253


Hence, the required height is 25√3 m.


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