Q. 64.6( 12 Votes )
Let BC = s; PC = t
Let height of the tower be AB = h.
∠ABC = θ and ∠APC = 90° - θ
(∵ the angle of elevation of the top of the tower from two points P and B are complementary)
Multiplying eq. 1 and eq. 2, we get
⇒ h2 = st
⇒ h = √st
Hence the height of the tower is √st.
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