Q. 6

# A diagonal of a p

Let ABCD is a parallelogram and diagonal AC bisect A.

Now,

AB||CD and AC is a transversal.

CAB = ACD

Again, AD||BC and AC is a transversal.

DAC = ACB

Now,

A = C

A = C

DAC = DCA

But, AB = CD and AD = BC (Opposite sides of parallelograms)

AB = BC = CD = AD

Thus, ABCD is a rhombus.

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