Q. 3 B

# The sum of n terms of an A.P. is 3n2+ 5n. Find the A.P. Hence, find its 16th term.

Answer :

Sn = 3n2 + 5n

Taking n = 1, we get

S1 = 3(1)2 + 5(1)

S1 = 3 + 5

S1 = 8

a1 = 8

Taking n = 2, we get

S2 = 3(2)2 + 5(2)

S2 = 12 + 10

S2 = 22

a2 = S2 – S1 = 22 – 8 = 14

Taking n = 3, we get

S3 = 3(3)2 + 5(3)

S3 = 27 + 15

S3 = 42

a3 = S3 – S2 = 42 – 22 = 20

So, a = 8,

d = a2 – a1 = 14 – 8 = 6

Now, we have to find the 15th term

an = a + (n – 1)d

a16 = 8 + (16 – 1)6

a16 = 8 + 15 × 6

a16 = 8 + 90

a16 = 98

Hence, the 16th term is 98.

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