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Q. 125.0( 12 Votes )

ABC is an isosceles triangle right angled at B. Similar triangles ACD and ABE are constructed on sides AC and AB. Find the ratio between the areas of ΔABE and ΔACD.

Class 10th AP- Mathematics 8. Similar Triangles

Answer :

Given, ABC is an isosceles triangle in which ∠B = 90°

Need to find the ratio between the areas of Δ ABE and Δ ACD

⇒ AB = BC

⇒ By Pythagoras theorem, we have AC² = AB² + BC²

⇒ since AB = BC

⇒ AC² = AB² + AB²

⇒ AC² = 2 AB² …..eq(1)

⇒ it is also given that Δ ABE ∼ Δ ACD

(ratio of areas of similar triangles is equal to ratio of squares of their corresponding sides)

⇒ =

⇒ = from 1

⇒ =

∴ ar(Δ ABC):ar(Δ ACD) = 1:2

Hence the ratio is 1:2

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PREVIOUSIn the given figure, ABC is a triangle right angled at B. D and E are points on BC trisect it.Prove that 8AE2 = 3AC2 + 5AD2.

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