# A square is inscr

Given, ΔABC with A = 90 and

AB = AC …(i)

Subtracting eqn (ii) from (i),

BD = CF

Now, in ΔCFE and ΔEDB,

BD = CF

DE = EF

CFE = EDB = 90 (Side of square)

ΔCEF BED (By SAS)

CE = BE

Hence, vertex E of the square bisect the hypotenuse BC.

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