Q. 75.0( 7 Votes )

Through A, B and

Answer :


PQ||AB, PR||AC and RQ||BC.

In quadrilateral BCAR,

BR||CA and BC||RA

BCAR is a parallelogram

BC = AR …(i)

Now, in quadrilateral BCQA,

BC||AQ and AB||QC

BCQA is a parallelogram

BC = AQ …(ii)

Adding Eqn. (i) and (ii), we get

2BC = AR + AQ

2BC = RQ

Hence, proved.

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