# Express sin 67° + Cos 75° in terms of trigonometric ratios of angles between 0° and 45°

sin 67° + cos 75°

For expressing this into between 0° and 45° we need to know complementary angle formulas:

sin(90° - A) = cos A

cos(90° - A) = sin A

Hence,

Now we can break 67° as 90° – 23 °.

And 75° as 90° – 15°.

So,

sin 67° + cos 75° = sin (90° – 23°) + cos (90° – 15°)

sin 67° + cos 75° = cos 23° + sin 15°

(Since, sin(90°- A) = cos A)

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