# ABC is an isoscel

Given:- AB=AC and ABC is isosceles triangle

CD||BA

Formula used:- sum of angles of triangle is 180°

Solution:-

As Δ ABC is a isosceles triangle

ABC= ACB

ABC+ ACB+ CAB=180°

2 ACB+ CAB=180°

*As BAQ is a straight line

CAB=180° - 2 DAC

Putting value of CAB in above equation 1

2 ACB+180° - 2 DAC=180°

2 ACB =2 DAC

ACB = DAC

If;

There is ACB = DAC and AC is the transverse

these are equal by alternate angles

In ABCD

If;

If both pair of sides of quadrilateral are parallel

Conclusion:-

ABCD is a parallelogram

And DAC = BCA

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